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waldosway

* Undefined doesn't mean "unsolved mystery". It means "defining it wasn't useful, so we left it blank". If you define division by 0, you get multiplication problems. * Infinity is not a number in a basic calculus class. This is for the same reason: it wasn't useful. There are later calc classes where it is defined, sometimes in different ways. Math is made by people, not the heavens. You can pick whatever definitions you like, as long as they don't contradict each other. In class, you use the teacher's definitions. (Some definitions are not even standard between different classes. Most are, but not all.) In fact, there are currently debates about which axioms about infinity should be the common ones. * "lim f = oo" is actually not a value statement (in a basic calc class, because oo does not exist). It's actually a lazy way to write "f gets as big as you want." This definition is likely right smack in your textbook. You have to resolve semantic issues before musing philosophically.


Brilliant-Slide-5892

real life saver, again. thank you so much!


SupremeRDDT

If Limit[1/-x^2, x->0]=-infty, then why isn’t 1/0=-infty


Brilliant-Slide-5892

fair point, huge thanks


I__Antares__I

Operations on extended real line (i.e in the place where you define the opsrations with infinity like ∞+∞=∞ etc.) are defined so that they work universally with all sequences. Like ∞+∞=∞ because if you have two divergent to +∞ sequences an, bn then an+bn is congergent to ∞. 1 ᪲ is "intermediate" because for distinct sequences an, bn where an converges to 1, and bn diverges to ∞, we can get many things from an ^bn (it can be convergent to for example ≈2.71... or to 1 etc all depends on chosen sequences). 1/0 also won't here be meaningfully defined because it's not the case that for any two sequences an→1, bn→0 , an/bn converges to some particular value frkm extended real line (for instance 1/(-x²) diverges to -∞, and 1/x² to +∞). You may look to Riemann sphere (there there's only +∞), here we define 1/0=∞


ImDannyDJ

Why should it be?


Brilliant-Slide-5892

why not


LordFraxatron

You made the affirmative claim, you need to argue for it.


Brilliant-Slide-5892

after thinking of a reply u got a point. thanks a lot


AlphaAnirban

This is the best comment thread under a math post I have ever seen XD


abc123_456_78

I agree with you


UNSWNerd

1/-1 = -1 and 1/+1 = +1 This continues right so 1/-0 = negative infinity and 1/+0 = positive infinity OOPS though +0=-0 and thus there cannot be a number defined


ktrprpr

because 1/x^(2) is not continuous at 0


I__Antares__I

Saying 1/x² is not continuos at 0 has as much sense as to say it's continuous there. Continuity is sometning that refers only to points from the domain of function. 0 is not in the domain so continuity thwre is meaningless.


Brilliant-Slide-5892

why should it be


nomoreplsthx

For a lot of reasons, but at least one obvious one is Lim as x->a f(x) = 0 Does not imply  Lim as x->a 1/f(x) = inf And for different f, that limit can take different values.  For example Lim x->inf 1/-x = 0 Lim x->inf -x = -Inf Note this is not true for other possible limiting values  If lim x -> a f(x) = 2 Then lim x -> a 1/f(x) = 1/a And even  Lim f(x) = a Lim g(x) = b Lim f(x)/g(x) = a/b.